Question

n operational amplifier circuit is shown in Figure 3-1 +5 V 25 kQ 12.5 k2 5 kQ D, Figure 3-1. i) Show that when the input voltage V, is set at 0 V, diode Dz is off and diode Di has a current of 0.20 mA flowing through it. ii) Show that when v 1 V, Di is just beginning to stop conducting, whereas D2 is just beginning to start conducting. iii) Construct the VTC for this circuit. iv) Sketch the output Vour which would be observed if the input Vs were a triangular waveform swinging between -2.5 V and +2.5 v Total 25 PER CODE.. ELEC317.PAGE...6...OF ...7.CONTINUED
Just question iv)plz
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Answer #1

We shall solve this problem in a step-by-step manner

Before answering iv) we have to look at the results we get after solving i) and ii).

It gives two regions of operation

the region of operation 1) Diode D1 is off and Diode D2 is on when Vg is varying from -2.5V to -1V

the region of operation 2) Diode D1 is on and Diode D2 is off when Vg is varying from -1V to +2.5V

Draw the circuit during the first region of operation (ie Diode D1 is off and Diode D2 is on)

+5 V La.Sku VOUT CANT TALS OTHER Da) LouT

Now analyse the circuit and solve for Vo which will give the output voltage variation when Vg is between -2.5V to -1V

Use KCL and virtual short concept for analysis

Appl さing kCL@ UT V, (ナ 0 v

Draw the circuit during the second region of operation (ie Diode D1 is on and Diode D2 is off) and analyse the circuit

Here (since Diode D2 is off) Vo is freely hanging connected to node b through 12.5kohm. Also, node b is grounded because of virtual ground concept. Hence it is as good as Vo is grounded.

Becau,e 125 kn D, ON SHORT6D OVTPUT VoLTAGS

Now draw the input-output waveform

0 (vouTs) +3,75 2.5 +1,a5 -0,5 8.75 0 8 5V -0,5 0 a15 0

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