Mutation in the S189D chymotrypsin in general increases the trypsin & likely activities 100 times. Also the mutant S 189 D in combination with A226G undergoes auto activation. In mutants, the Km values is higher than the non mutants. Like kcat values also increases in the mutants as compared to the non mutants.
Hence, option A is correct
A S189V mutation-in chymotryspin would have as compared to the wild type. A. increased KM B....
A H57K mutation in chymotrypsin would have as compared to the wild type. decreased KM decreased kcat increased KM O no difference (mutation has no effect) Which of the following is true about the pyruvate dehydrogenase complex (PDHC)? Decarboxylation occurs first. OPDHC catalyses a substrate level phosphorylation. The sulfur atoms in the lipoamide arm assist by carrying protons. OPDHC catalyses the most rate limiting reaction in cellular respiration. NADH is produced by E1. The PDHC contains 5 enzymes.
der the owng reaction ADPY. AIP I the net AG" for the reaction is 32 4. what is the AG" for X -> Y? Your Answer: A E72K mutation in CPA would have as compared to the wild type. decreased KM no difference (mutation has no effect) decreased kcat increased KM
Below are the Kcat and Km values for 5 hypothetical enzymes. Which enzyme would have the largest specificity constant? Enzyme A - Kcat = 2.6 x 103 , Km = 4 x 10-4 Enzyme B - Kcat = 9 x 102 , Km = 6.1 x 10-6 Enzyme C - Kcat = 1.7 x 10-3 , Km = 3.2 x 105 Enzyme D - Kcat = 2.6 x 10-7 , Km = 4 x 104 Enzyme E - Kcat =...
How would a 50% increase in enzyme concentration affect the observed KM? A. KM unchanged B. KM increased by 1/2 C. cannot be determined D. KM decreased by 1/2
3. Below are several DNA sequences that are mutated compared with the wild-type sequence: 3’ - T A C T G A C T G A C G A T C - 5’. Each is a section of a DNA molecule that has separated in preparation for transcription, so you are only seeing the template strand. a. Construct the complementary DNA sequences (indicating 5’ and 3’ ends) for each mutated DNA sequence. b. Transcribe (indicating 5’ and 3’ ends) the...
If the wild type DNA sequence reads THE CAT ATE THE BIG RAT, what type of mutation would change the sequence to THE CAT ATT HEB IGR AT? a. missense b. nonsense c. deletion d. insertion e. silent
5. Consider the wild-type F8 gene. What would happen to the 1)
transcript
(mRNA) sequence and quantity, 2) to the protein (sequence,
quantity, function) and 3) the person’s
overall phenotype if they were homozygous (both copies of the
gene are the same) for a 3 base-pair
deletion in the:
i. First intron
ii. First exon
iii. The promoter
iv. 5’UTR
v. Last exon
6. What environmental factor could affect the phenotype caused
by an F8 null mutation?
Thrombophilia is a...
What would be the effect of each type of the following mutations? a,) Mutation that destroys the function of eukaryotic DNA polymerase alpha. b.) A mutation that destroys the 5' to 3' exonuclease activity of DNA polymerase I.
Below is the coding DNA sequence for a gene called tribble, including the wild-type and several mutant alleles. For each mutant allele, fully classify the mutation and its effect in the amino acid sequence. Wild-type 5'-ATGGCAACTACATATAGCACAGTTTGAACC-3' a. Mutant allele #1 5'-ATGGCAACTACATAAAGCACAGTTTGAACC-3' b. Mutant allele #2 5'-ATGGCAACTACATATAGCATAGTTTGAACC-3' c. Mutant allele #3 5'-ATGGCAACTACATACAGCACAGTTTGAACC-3' d. Which mutant allele is most likely to be a knockout and why?
Question 4 Multi-Part Questions. Make sure to answer ALL parts (a-c)! You have isolated two versions of the same enzyme, a wild type and mutant. The marteses You have determined the following kinetic characteristics for each of the enzymes. Vmax Wild Type Km 200 umol / min 0.2mm Mutant 2 umol / min 20mm and the reaction is a two-step reaction where k.1 is much larger than k3, which enzyme has the higher affinity for substrate to you You determine...