I wrote a Matlab program for the figure below. When I plot the waves, they look the same. Why do the two waves frequencies look same and How do I avoid it? (I really do need this part of the question answered.)
N = 200; % Total number of time domain samples in simulation.
Fs = 100 ;% sampling frequency.
F1 = 10; % frequency of wave - 1.
F2 = 90; % frequency of wave - 2.
phi = 0; % zero phase signal.
t=0:(1/Fs):(N-1)/Fs; % time samples.
y1 =sin(2*pi*F1*t+phi); %first sinwave.
y2= sin(2*pi*F2*t+phi); %second sinwave
% plotting above functions in continuous and discrete time.
subplot 221; plot(t, y1); xlabel('Time in sec F1 = 10Hz'); ylabel('Amplitude'); grid on;
subplot 222; plot(t, y2); xlabel('Time in sec F2 = 90 hz'); ylabel('Amplitude'); grid on;
Original output by your code:
Why both waveform look same even frequency of both signal is different:
- we are sampling a sine wave signal with frequency of 100Hz.
- Frequency of first sine wave is 10Hz and as per Nyquist formula sampling frequency must be greater than equal to 2 time of highest frequency( fs >= 2*f). This condition is satisfied for first sine wave.
- In case of second sine wave, highest frequency is 90Hz and according to above formula sampling frequency must be greater than equal to 2*90 = 180Hz. But in this case it is not satisfied sampling frequency is 100Hz instead of 180Hz.
update code : Fs = 200 ;% sampling frequency.

- In above picture we can see both waveform is having different frequency. We have divided plot window in 2x2 part and we are using only first 2 part.
-We can divide into 2 part only in vertical part.
update code:
subplot (2,1,1); plot(t, y1); xlabel('Time in sec F1 = 10Hz'); ylabel('Amplitude'); grid on;
subplot (2,1,2); plot(t, y2); xlabel('Time in sec F2 = 90 hz'); ylabel('Amplitude'); grid on;

- As we are having very low sampling rate for high frequency sine wave. Due to that in above diagram you can see second sine wave is having different magnitude.
- To avoid this we can increase sampling frequency further
update code: Fs = 1000 ;% sampling frequency.

matlab code:
%//////////////////////////////////////////////////////////////////////////
N = 200; % Total number of time domain samples in
simulation.
Fs = 1000 ;% sampling frequency.
F1 = 10; % frequency of wave - 1.
F2 = 90; % frequency of wave - 2.
phi = 0; % zero phase signal.
t=0:(1/Fs):(N-1)/Fs; % time samples.
y1 =sin(2*pi*F1*t+phi); %first sinwave.
y2= sin(2*pi*F2*t+phi); %second sinwave
% plotting above functions in continuous and discrete time.
subplot (2,1,1); plot(t, y1); xlabel('Time in sec
F1 = 10Hz'); ylabel('Amplitude'); grid on;
subplot (2,1,2); plot(t, y2); xlabel('Time in sec
F2 = 90 hz'); ylabel('Amplitude'); grid on;
%//////////////////////////////////////////////////////////////////////////
- code which I have changed is in BOLD TEXT
I wrote a Matlab program for the figure below. When I plot the waves, they look...
Program from problem 1: (Using MATLAB)
% Sampling frequency and sampling period
fs = 10000;
ts = 1/fs;
% Number of samples, assume 1000 samples
l = 1000;
t = 0:1:l-1;
t = t.*ts; % Convert the sample index into time for generation and
plotting of signal
% Frequency and amplitude of the sensor
f1 = 110;
a1 = 1.0;
% Frequency and amplitude of the power grid noise
f2 = 60;
a2 = 0.7;
% Generating the sinusoidal waves...
Reproduce Figures 9.2b and 9.2c on MATLAB, assuming that the
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normalized amplitude (A=1). Each student group should
decide the power spectral density level of the channel noise.
Compute the Fourier transform of the periodic square wave.
clear all
close all
%%%%
T=12*pi; %number of period
x=linspace(0,T);
t=x/pi
y0=square(x); %square wave signal
y0ft=fft(y0); %calculating Fourier Transformof signal
y0fts=fftshift(y0ft);
y0ftFinal=abs(y0ft);
AWGN= rand(size(x)); %Calculating whit noise
Att=(1/3);
nSig= Att*AWGN;
y=y0+nSig; %Square wave...
NB! This task is required to be solved in matlab. this task also requires the use of the function displayDualSpectrum();
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Task - Frequency mixing
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MATLAB
code starts here ---------
clear
T0=2;
w0=2*pi/T0;
f0=1/T0;
Tmax=4;
Nmax=15;
%---
i=1;
for t=-Tmax: .01:Tmax
T(i)=t;
if t>=(T0/2)
while (t>T0/2)
t=t-T0;
end
elseif t<=-(T0/2)
while (t<=-T0/2)
t=t+T0;
end
end
if abs(t)<=(T0/4)
y(i)=1;
else
y(i)=0;
end
i=i+1;
end
plot(T,y),grid, xlabel('Time (sec)'); title('y(t) square wave');
shg
disp('Hit return..');
pause
%---
a0=1/2;
F(1)=0; %dc freq
C(1)=a0;
for n=1:Nmax
a(n)=(2/(n*pi))*sin((n*pi)/2);
b(n)=0;
C(n+1)=sqrt(a(n)^2+b(n)^2);
F(n+1)=n*f0;
end
stem(F,abs,(C)), grid, title(['Line Spectrum: Harmonics = '
num2str(Nmax)]);
xlabel('Freq(Hz)'), ylabel('Cn'), shg
disp('Hit return...');
pause
%---
yest=a0*ones(1,length(T));
for n=1:Nmax
yest=yest+a(n)*cos(2*n*pi*T/T0)+b(n)*sin(2*n*pi*T/T0);...
please help me with this MATLAB CODE and
explain to me what each line does and what is used for?
leave your comments as words, not as pictures.
.....................................................................................................................................................................
clear all; close all; % For a script file, you better start with
clear all and close all
% However, for a fucntion, you better NOT to start
% with them
%% End of cell mode example
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t = 0:0.1:5;
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Can you please help me answer Task 2.b?
Please show all work.
fs=44100; no_pts=8192;
t=([0:no_pts-1]')/fs;
y1=sin(2*pi*1000*t);
figure;
plot(t,y1);
xlabel('t (second)')
ylabel('y(t)')
axis([0,.004,-1.2,1.2]) % constrain axis so you can actually see
the wave
sound(y1,fs); % play sound using windows driver.
%%
% Check the frequency domain signal. fr is the frequency vector and
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fr=([0:no_pts-1]')/no_pts*fs; %in Hz
fr=fr(1:no_pts/2); % single-sided spectrum
f1=abs(fft(y1)); % compute fft
f1=f1(1:no_pts/2)/fs;
%%
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