Question

5’ctaagATGCCGATgtttaaaagACTAAAAGTTAAgtttcacagTTCAGGGCAACGGCGGTGAgtaaaa3’

3’gattcTACGGCTAcaaattttcTGATTTTCAATTcaaagtgtcAAGTCCCGTTGCCGCCACTcatttt5’

(3) Point mutations can be transition, transversion, synonymous change, and/or non-

synonymous change. What types do the following mutations belong to? For the

above DNA sequence (position index starts at 1 using the biologist’s notation),

(1). a mutation occurs at position 8, changing G to A. (2). a mutation occurs at

position 11, changing G to A. (3). a mutation occurs at position 15, changing t to

c. (4). a mutation occurs at position 12, changing A to C. (5). create a stop codon

by introducing a mutation, be it point mutation or indels (insertion/deletion). (10

points).

Answer 1

mRNA will be formed from 3' to 5' DNA,

5’ ctaagAUGCCGAUguuuaaaagACUAAAAGUUAAguuucacagUUCAGGGCAACGGCGGUGAguaaaa 3' (mRNA)

Removal of introns and joining of exons,

5’ AUG CCG AUA CUA AAA GUU AAU UCA GGG CAA CGG CGG UGA 3'

Amino acids formed after translation,

N met pro ile leu lys val asn ser gly gln arg arg STOP C

Now you have to perform mutations on this sequence,

mRNA,

3' ctaagAUGCCGAUguuuaaaagACUAAAAGUUAAguuucacagUUCAGGGCAACGGCGGUGAguaaaa 3'

1. G to A at 8th position,

AUG to AUA

First amino acid will change from met to ile

Mis sense mutation

2. G to A at 11th position,

CCG to CCA

pro will remain pro

No change

Silent mutation

3. T to C at 15th position

This is occuring in intron, which do not participate in translation

No change

Silent mutation

4. A to C at 12th position

CUA to CUC

leu will remain leu

No change

Silent mutation

5. Change C to G at 46th position

UCA to UGA

Ser to STOP

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