Question

I only need answer to number 3 (on bottom) which was not answered on the last one that was posted.

li $s6,268500992

li $s3,3

li $s5,10

li $t0,10

sw $t0, 0($s6)

sw $t0, 4($s6)

sw $t0, 8($s6)

sw $t0, 12($s6)

sw $t0, 16($s6)

sw $t0, 20($s6)

sw $t0, 24($s6)

sw $t0, 28($s6)

li $t0,2

sw $t0, 32($s6)

loop: sll $t1,$s3,2

add $t1,$t1,$s6

lw $t0,0($t1)

bne $t0,$s5,exit

addi $s3,$s3,1

j loop

exit:

1. _{Already answered.... Draw the memory and its contents starting from address 268500992.}
2. _{Already answered..... What does the final value of $s3 represent?}
3. Need Answer... After understanding the provided program, write your own program using loops to find how many times the same number (10) is stored in the memory

Answer 1

MIPS :program (the result is stored in $t0 ) :-

li $s6,268500992   #starting address
li $s3,9           #no of word elements need to be counters
li $t0,0           #counter
li $t1,10

LOOP_START:
   beq $s3,$0,exit           #loop condition
   lw $t2,0($s6)           #extracting the value
   bne $t1,$t2,NEXT_ELE   #checking for extracted is 10 or not
   addi $t0,$t0,1           #if 10 then counter is increased
NEXT_ELE:
   addi $s6,$s6,4       #pointing to next element
   addi $s3,$s3,-1       #decrement the counter
   j LOOP_START

exit: