you construct an E.coli strain that carries mutation in the genome that impact lactose utilization. describe what would happen if you were to use an E.coli strain that has a mutation in the binding site for CAP so that CAP will no longer bind. Explain how it will differ from the normal wild type E.coli
When glucose is present in the cell, cAMP is not synthesized. Glucose inhibits the enzyme adenylated cyclase which converts ATP into cAMP. cAMP binds to CAP and forms a complex that binds to the promoter of the lac operon. cAMP-CAP complex helps RNA polymerase in its promoter binding.
When cell utilized all its glucose, cAMP is synthesized and lac operon is activated.
If there is a mutation in the CAP such that it cannot bind to the promoter, RNA polymerase will not be able to bind lac promoter and lac operon will be in repressed condition even in the absence of glucose and presence of lactose.
you construct an E.coli strain that carries mutation in the genome that impact lactose utilization. describe...
A. Which strain is the wild-type E.coli? Explain how you know
this.
B. Which strain contains the nonsense mutation in the CRP
protein gene? Explain how you know this.
C. Which strain contains the deletion mutation in the lac operon
operator sequence? Explain how you know this.
knowledge about the lac operon system AND knowledge Problem set about the Lac operon (these problems require knowledge about the lac operon system AND about consequences of mutations) You are working with three...
you grow E.coli that have a mutation in their Operator gene (O) so that the operon is constitutively active. what would happen when this mutant is grown in media that contains glucose, but not lactose? select all answers!! A- the repressor would change shape B- the repressor would bind the operator c- the structural genes would be transcribed D- RNA polymerase would bind the promoter
The lac operon contains a DNA sequence known as the lac promoter (P or P+ for wild type; P– for mutant (RNA polymerase does not bind)) that serves as the RNA polymerase binding site. The lac operon also contains a DNA sequence known as the Lac operator (O or O+ for wild type; O– or Oc for mutant (lac repressor cannot bind)) which is the binding site for lac repressor. The lac repressor, a protein, is encoded by the lac...
Briefly explain your answers to the following questions. A mutation (Mutation A) in the lac operon of E. coli leads to an inability to ferment lactose, and the expression of the operon is always off. Introduction into the mutant of an F' factor containing the wild type lac operon does NOT restore the ability to ferment lactose, i.e., there is no expression of the operon from the plasmid either. a. What is the probable nature of Mutation A? Is the...
help with this genetic problem
You have a mutant E.coli with a lac operon (lacMuT) which is not responding to lactose control You create an F episomal plasmid with the wild-type lac operon (lacW) and transform it into your mutant E. coli Genotype Mutant (lac) Mutant (lac Merizygote (lacMUT+ lacMUT)No Merizygote (lalacYes Lactose Added? Beta-galactosidase activity 100% 100% 100% 200% MUT Yes MUT MUT Is the mutation in the lacl trans-factor or the lacO cis-element? Describe the likely mutation and...
Imagine you are carrying out research on the lac
operon. You isolate six mutations in the lac operon by
measuring the amount of beta-galactosidase made in mutant cell line
under three different conditions: no lactose/no glucose; lactose
only; and lactose/glucose. Your results are shown in the table.
Strain
No Lactose, No Glucose
Lactose
Lactose, Glucose
Wild-type
None
High
Low
Mutant 1
None
None
None
Mutant 2
None
None
None
Mutant 3
None
Low
Low
Mutant 4
None
Low
Low
Mutant...
A. You are studying a strain of bacteria that carries a temperature-sensitive mutation in one of the genes required for DNA replication. The bacteria grow normally at the lower temperature, but when the temperature is raised they die. When you analyze the remains of the bacterial cells grown at the higher temperature you find evidence of partly replicated DNA. When the strands of this DNA are separated by heating, numerous single-stranded DNA molecules around 1000 nucleotides long are found. Which...
You are asked to develop a demonstration to show how the
lac operon works. You decide to use X-gal and IPTG to
determine if the enzyme ?-galactosidase is active. X-gal is a
lactose analog that turns blue when metabolized by ?-galactosidase,
but it does not induce the lac operon. IPTG is an inducer
of the lac operon, but is not metabolized by ?-galactosidase.
a. (2pts) Which of the following would you expect to bind to
?-galactosidase. Circle all that apply....
3. Consider a hypothetical strain of E. coli (strain 401) that contains two mutations that affect tryptophan biosynthesis. The first mutation is a single nucleotide substitution that converts the second tandem Trp codon in region 1 of the Trp leader sequence into a stop codon (see slides 2-7 of Lecture 24 on iLearn) trp structural genes trpE trpD trpC trpB trpA PO Trp Leader Met-Lys-Ala-lle-Phe-Val-Leu-Lys-Gly-Trp-Trp-Arg-Thr Ser- Stop Assume that strain 401 also contains a mutation in the gene for the...
1. (1 pt) If a gene is repressible and under positive control, A. Is the regulatory protein an activator or repressor? B. Explain how an effector molecule, which binds to the regulatory protein, alters the regulatory protein’s ability to regulate expression of the gene. 2. (1 pt) Cis and trans are two terms used to describe mutations. A. Explain the molecular difference between these terms. B. indicate which type of mutation (cis or trans) is dominant to wild-type and which...