The Drosophila melanogaster (fruit fly) genome is 120 million base pair (bp) long. The restriction enzyme...
The Drosophila melanogaster (fruit fly) genome is 120 million base pair (bp) long. The restriction enzyme EcoRI is a 6-base cutter. If EcoRI was used to digest the entire Drosophila genomic DNA, calculate the number of cuts estimated theoretically.
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I have solved the above question in the picture below, so please take a look-
The number of cuts required to completely digest the genome is 20 million cuts. Look at the picture below for the calculations.
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The Drosophila melanogaster (fruit fly) genome is 120 million
base pair (bp) long. The restriction enzyme...
EcoRI is a common restriction enzyme used in cloning experiments. Its restriction sequence is G’AATTC. The...
EcoRI is a common restriction enzyme used in cloning experiments. Its restriction sequence is G’AATTC. The strand is cut at the position of the apostrophe. The 50 base pair sequence shown below contains one or more EcoRI sites. Find them and circle them. Then count the resulting size (in base pairs – bp) of the DNA fragments (pieces) left over after using EcoRI to cut this DNA sequence. Circle the EcoRI sites in the sequence below. 1- ggagaattcgctgtacgaggttaaccccgatgccATGGCATGAATTCGTG -50 List...
Questions 9-12 deal with SSR loci in Sam's genome. Remember that SSRs (simple sequence repeats) are...
Questions 9-12 deal with SSR loci in Sam's genome. Remember that SSRs (simple sequence repeats) are tandem (next to each other) repeats of short sequences (a few bp). Such tandem repeats are located at specific sites scattered throughout the genome. Individuals vary in the number of repeats at each site sites can have up to 100 repeats. Each locus with the same repeats is called an SSR ocus DNA was extracted from Sam's white blood cells and cut with a...
Hi I have a problem with number 5, it involves gel analysis results. There are 2 parts, a,b,c. For A Im sure you need to make a graph with distance in (cm) on the vertical axis and log10 bp on the hor...
Hi I have a problem with number 5, it involves gel
analysis results. There are 2 parts, a,b,c. For A Im sure you need
to make a graph with distance in (cm) on the vertical axis and
log10 bp on the horitzontal. I need help figuring out where to
start and what to do. Please help!
The following question will provide practice in interpreting and analyzing gel results You obtained the DNA electrophoresis gel below. Three samples of lambda phage...
Chromosomal and plasmid DNA can be cut into manageable pieces by restriction enzymes. Using agarose gel...
Chromosomal and plasmid DNA can be cut into manageable pieces by
restriction enzymes. Using agarose gel electrophoresis, the DNA
fragments can be separated on a gel, based on their lengths. In
order to see the fragments, a stain is typically added to the gel.
The size of each fragment can be determined by comparing each one
to a DNA molecular weight marker of known size.
Below is a map of pBR22 plasmid. The position and base pair
number of the...
help with questions 5 to 10 please PCB 3023L Lab #4 Protocol & Worksheet (30pt) You...
help with questions 5 to 10 please
PCB 3023L Lab #4 Protocol & Worksheet (30pt) You may work in your lab groups durine class. but all written answers must be completed individually in your own words. 1) Using the plasmid map for orientation 1 and the cDNA map as a guide, complete the plasmid map for orientation #2. (4pt) 612 1318 1 - EcoRi EcoRI Xbal ECORV -Xbal- 1662 +Bell EcoRI EcoRV Not FP -- Xhol X 2015 PRSP +...
2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving...
2. A dominant allele H reduces the number of body bristles that Drosophila flies have, giving rise to a “hairless” phenotype. In the homozygous condition, H is lethal. An independently assorting dominant allele S has no effect on bristle number except in the presence of H, in which case a single dose of S suppresses the hairless phenotype, thus restoring the "hairy" phenotype. However, S also is lethal in the homozygous (S/S) condition. What ratio of hairy to hairless flies...
Questions 9-12 deal with SSR loci in Sam's genome. Remember that SSRs (simple sequence repeats) are tandem (next to each other) repeats of short sequences (a few bp). Such tandem repeats are located at specific sites scattered throughout the genome. Individuals vary in the number of repeats at each site sites can have up to 100 repeats. Each locus with the same repeats is called an SSR ocus DNA was extracted from Sam's white blood cells and cut with a...
Hi I have a problem with number 5, it involves gel
analysis results. There are 2 parts, a,b,c. For A Im sure you need
to make a graph with distance in (cm) on the vertical axis and
log10 bp on the horitzontal. I need help figuring out where to
start and what to do. Please help!
The following question will provide practice in interpreting and analyzing gel results You obtained the DNA electrophoresis gel below. Three samples of lambda phage...
Chromosomal and plasmid DNA can be cut into manageable pieces by
restriction enzymes. Using agarose gel electrophoresis, the DNA
fragments can be separated on a gel, based on their lengths. In
order to see the fragments, a stain is typically added to the gel.
The size of each fragment can be determined by comparing each one
to a DNA molecular weight marker of known size.
Below is a map of pBR22 plasmid. The position and base pair
number of the...
help with questions 5 to 10 please
PCB 3023L Lab #4 Protocol & Worksheet (30pt) You may work in your lab groups durine class. but all written answers must be completed individually in your own words. 1) Using the plasmid map for orientation 1 and the cDNA map as a guide, complete the plasmid map for orientation #2. (4pt) 612 1318 1 - EcoRi EcoRI Xbal ECORV -Xbal- 1662 +Bell EcoRI EcoRV Not FP -- Xhol X 2015 PRSP +...
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