Answer 1. Vmax plays important role in enzyme action. Increase the substrate concentration indefinitely doesn't increase rate of an enzyme catalyzed reaction beyond certain point. This point is reached when there is enough substrate molecules to completely saturate the active site of an enzyme. Vmax reflects how fast enzyme can catalyze reaction.
Answer 2. As the concentration of substrate increase, the enzyme becomes saturated with substrate. Adding more substrate will not affect the rate of the reaction to any significant effect. The rate of reaction when the enzyme is saturated with substrate is maximum rate of reaction.
Answer 3. Vmax obviously increases when the enzyme concentration is changed because of the amount of enzyme affects the rate of turnover given sufficient substrate.
Answer 4. Km is the concentration of substrates when the reaction reaches half of Vamx. A small Km indicates high affinity since it means the reaction can reach half of the Vmax in a small number of substrate concentration. This small Km will approach Vmax more quickly than high Km value.
Answer 5. Specific activity is a term used to measure the rate of reaction of an enzyme with a substrate. Specific enzyme activity is a measure of the purity of an enzyme solution and is quoted as units/mg. Measures purity of an enzyme solution and used in protein isolation methods to indicate the percentage of purification.
1. In your own words, describe what is the VMAX of an enzyme. 2. What would...
What is the velocity of a Michaelis-Menten enzyme reaction (in terms of vmax) when the concentration of substrate is 4 times the value of KM? Show your work.
For an enzyme that follows the Michaelis-Menten kinetic, what substrate concentrations (relative to Km) are needed for the speed of the reaction to be 0.12 there vmax 0.25 there vmax 0.5 there vmax 0.9 there vmax.
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...
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Q1. WHAT ARE ENZYMES? HOW DOES ENZYME-SUBSTRATE BINDING TAKES PLACE? Q2. IN MICHAELIS -MENTEN GRAPH, WHY DOES THE CURVE REACHES PLATEAU? Vmax Reaction velocity (v) Vm/2 Km Substrate concentration (S) Q3. IN MICHAELIS MENTEN GRAPH, HOW WOULD YOU INCREASE VELOCITY BEYOND Vmax? Q4. SMALLER VALUE OF THE MICHAELIS CONSTANT (Km) REFLECTS HIGHER EFFICIENCY OF THE ENZYME. (TRUE/FALSE).
The following chart shows the data for the oxidation of a substrate to enzyme. The reaction is followed by monitoring the change in absorbance at 540nm. Create a Michaelis-Menten plot and a Lineweaver-Burk plot. Determine from each plot the KM and Vmax. [S] (mM) 0.3 0.6 1.2 4.8 Rate (ΔAbs/min) 0.020 0.035 0.048 0.081
The relation between Reaction Velocity and Substrate Concentration: Michaelis-Menten Equation a) At what substrate concentration would an enzyme with a kcat of 30.0 s-1 and a Km of 0.0050 M operate at one-quarter of its maximum rate? b) Determine the fraction of Vmax that would be obtained at the following substrate concentrations: [S]=Km/2, [S]=2Km, [S]=10Km
For an enzyme that displays Michaelis-Menten kinetics, what is the reaction velocity v (as a percentage of Vmax) ,observed at each of the following substrate concentrations. (Ex, v = xVmax, where x = an integer, fraction, or decimal number (two decimal places)) a) [S] = 0.1 Km _________ b) [S] = 2 Km _________ c) [S] = 10 Km _________
3. Why is an allosteric enzyme more sensitive to substrate concentration around Km values than a Michaelis-Menten enzyme with the same Vmax? 4. Explain how pH and temperature influence enzyme activity. ( A Lineweaver-Burk (double reciprocal) plot was used to compare the effects of three different reversible inhibitors (A, B and C) on an enzyme. The plot of 1/V vs 1/[S] for the enzyme with no inhibitor is shown in a solid black line. The plot of 1/V vs 1/[S]...
1. Show, using the Michaelis-Menten equation, that when [S] >>> Km, vo = Vmax. Show, using the M-M equation that when [S] <<<Km, vo =[S][Et]kcat/Km. 2. What is Vmax? Provide both a mathematical and written description of Vmax? How can Vmax be experimentally altered? How can we use Vmax to determine the turnover number (kcat) of an enzyme-catalyzed reaction? What is the major challenge of determining Vmax from an Michaelis-Menten plot?
b. For an enzyme that displays Michaelis-Menten kinetics, what is the initial velocity as a function of Vmax when: a. [S] Km b. S] 0.1 Km c. [S] 50Km c. What will be the initial velocity (yo) for an enzyme that has Km 2.5 [S]? Your answer will be a fraction of Vmax a.