The last expert gave me the wrong answers, please don't steer me wrong. All answers to 4 decimal places please.
A compound microscope consists of a 3× eyepiece & a 34× objective 21 cm apart. Assuming the final image is in focus with the eye relaxed, determine the following:
Microscope magnification =
Eyepiece focal length =
Objective focal length =
Distance of object from objective =
The last expert gave me the wrong answers, please don't steer me wrong. All answers to...
A compound microscope consists of a 3× eyepiece & a 34× objective 21 cm apart. Assuming the final image is in focus with the eye relaxed, determine the following: Microscope magnification = Eyepiece focal length = Objective focal length = Distance of object from objective =
A compound microscope consists of a 4× eyepiece & a 42× objective 30 cm apart. Assuming the final image is in focus with the eye relaxed, determine the following: Objective focal length = Distance of object from objective =
Please help me with part B and C they are both wrong.
The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens has a magnification of 62x and the eyepiece has a magnification of 10 %. Assume that the image of the objective lies very close to the focal point of the eyepiece. Part A Calculate the overall magnification of the microscope. M = 620 X Submit Previous Answers Correct Part B Calculate the...
A compound microscope has the objective and eyepiece mounted in a tube that is 18.8 cm long. The focal length of the eyepiece is 2.55 cm , and the near-point distance of the person using the microscope is 24.0 cm . If the person can view the image produced by the microscope with a completely relaxed eye, and the magnification is -4516, what is the distance between the objective lens and the object to be examined?
A compound microscope has the objective and eyepiece mounted in a tube that is 20.0 cm long. The focal length of the eyepiece is 2.72 cm , and the near-point distance of the person using the microscope is 25.0 cm. If the person can view the image produced by the microscope with a completely relaxed eye, and the magnification is -4025, what is the focal length of the objective?
A microscope has a 9.0✕ eyepiece and a 63.0✕ objective 20.0 cm apart. (a) Calculate the total magnification. ___________✕ (b) Calculate the focal length of each lens. eyepiece _________cm objective _________cm (c) Calculate where the object must be for a normal relaxed eye to see it in focus. __________cm
Microscope - New A microscope has a 13.0 x eyepiece and a 64.0 x objective lens 22.0 cm apart. It has been adjusted for a RELAXED normal eye. Part A Calculate the total magnification. Part B Calculate the focal length for the EYEPIECE. Part C Calculate the image distance for the OBJECTIVE.
an object is 1.2 cm form the objective lens of a simple compound microscope that is adjusted for a relaxed normal eye. the objective and eyepiece are 18 cm apart and the eyepiece has a focal length of 4.8 cm. what is the focal length of the objective lens?
please I need answers to all questions because am
writing text on Friday.
7. Suppose an object such as a book page is held 7.50 cm from a concave lens of focal length -1C em. Such a lens could be used in eyeglasses to correct pronounced nearsightedness. (a) Using the thin le equations to calculate the location of the image. (b) What magnification is produced? (c) Use ray tracing get an approximate location for the image. 8. The left face...
(10 points: for full credit all work must be turned in) A microscope has a converging lens (the eyepiece) with a focal length of f; = 2.07 cm mounted on one end of a tube of adjustable length. At the other end is another converging lens (the objective) that has a focal length of f2. = 15.01 cm . When you place a small flea you want to examine at a distance of sy = 3.67 cm from the objective,...