Information regarding tasks in an assembly line run for an 8-hour shift each day is provided:
|
Task |
Proceeding Task (s) |
Tme (min) |
|
A |
- |
5 |
|
B |
- |
3 |
|
C |
- |
2 |
|
D |
A |
1 |
|
E |
B |
4 |
|
F |
C |
6 |
|
G |
D,E |
7 |
|
H |
G |
5 |
|
I |
F,G |
6 |
|
J |
H,1 |
4 |
|
K |
I |
3 |
a)What is the theoretical minimum number of stations for a shift output of 40 units?
B)if the line is balanced according to the desired cycle time and with one more than the minimum number of stations wht would be % idle time?
Output = 40 units
Shift time = 8 hours or 480 minutes
Cycle time= Shift time / Output = 480/40 = 12 minutes
Sum of all task times = 46 minutes
Theoretical minimum number of stations = 46 / 12 = ~4 workstations
Idle time when there are 4+1 = 5 Workstations = Sum of task time / Number of workstations * Cycle time = 46 / (5*12) = 46/60 = 76.67%
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