Question

Three resistors, R1 2.0 Ω, R2:4.0 Ω, and R3:6.0 Ω are connected as shown in the figure below. For Circuit 1 (left), (a) Find the equivalent resistance of the combination; .e. [Req1] in Ohms. (b) Find the current that passes through the combination if a potential of 8.0 V is applied to the terminals: L.e. [Itot1] in A (c) Find the voltage across and the current through each resistor; L.e R1: Voltage: [VR11] V and Current: [IR11] A R2: Voltage: [VR21] V and Current: [IR21] A R3: Voltage: [VR31] V and Current: [IR31] A Req1 is equal to ?? Ohrm

Answer 1

R_1 = 2 ohm, R_2 = 4 R and R_B = 6 ohm For circuit - 1 R_2 and R_2 in parallel R_eq of R_2 and R_3 R_2^1 = R_2 R_3/R_2 + R_3 = 6 times 4/10 = 2.4 ohm R_2^1 and R_1 in series = R_1 + R_2^1 R_eq = 2 + 2.4 = 4.4 ohm R_eq = 4.4 ohm I = 8/R_eq = 8/4.4: I = 1.82 Amp (c) voltage across R_1 = I_1 R_1 = 1.82 times 2 v_R_1 = 3.64 volt \r\n V_R_2 = ? I_R_2 = I_1 times R_3/R_2 + R_3 I_R_2 = 1.82 times .6 I_R_2 = 1.092 Amp V_R_2 = 4.368 volt V_R_3 = ? I_R_3 = I_1 - I_2 = 0.728 Amp V_R_3 = 0.728 times 6 V_R_3 = 4.368 volt circuit 2 R_2 and R_3 in parallel so equivalent of both implies R_2^1 = R_2 R_3/R_3 + R_2 = 2.4 ohm Now R_1 and R_2^1 in parallel