Question

Three resistors, R1-2.0 Ω, R2-4.0 Ω, and R3 6.0 Ω are connected as shown in the figure below. For Circuit 1 (left), (a) Find the equivalent resistance of the combination; t.e. Req1] in Ohms ) Find the current that passes through the combination if a potential of 8.0 V is applied to the terminals; L.e. [itot1) in Amps. (c) Find the voltage across and the current through each resistor; L.e. R1: Voltage: [VR11] V and Current: [IR11] A R2: Voltage: [VR21] V and Current: [IR21] A R3: Voltage: [VR31] V and Current: [IR31) A
Req1 is equal to ?? Ohms Answer Itot1 is equal to ?? Amps Answer: VR11 is equal to ?? Volts Answer: IR11 is equal to ?? Amps Answer:
Answer: IR21 is equal to ?? Amps Answer: VR31 is equal to ?? Volts Answer: on IR31 is equal to ?? Amps Answer:
For Circuit 2 (right), (a) Find the equivalent resistance of the combination; i.e. [Req2] in Ohms. (b) Find the current that passes through the combination if a potential of 8.0 V is applied to the terminals; L.e. [Ite (c) Find the voltage across and the current through each resistor; i.e. R1: Voltage: [VR12] V and Current: [IR12] A R2: Voltage: [VR22] V and Current: [IR22] A R3: Voltage: [VR32] V and Current: [IR32] A Req2 is equal to ?? Ohms Answer: Itot2 is equal to ?? Amps Answer: VR12 is equal to ?? Volts Answer:
IR12 is equal to ?? Amps Answer: VR22 is equal to ?? Volts Answer: IR22 is equal to ? Amps Answer: VR32 is equal to ?? Volts Answer:
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Answer #1

LEFT

R2 R3 parallel followed by R1 series

Reg = 2 + (4-1 + 6-1)-1- 22/5-4.4Ω

Total current

1 = V/Req = 8/4.4 1.82 Anıp

V across R2=V across R3=1R23 = 2.4 * 1.82 = 4.36

V across R1=1R1-2 * 1.82-3.63

I in R2

R3 R2R I2 ITot 1.82 0.6 1.1 Amp

I in R3

R2 R2R 13 = İTot 1.82 * 0.4 0.72 Amp

I in R1 is same as the total current, i.e., 1.82 A

RIGHT

All 3 resistance are in parallel.

Req (2-1 +4-1 + 6-1)- 1.1(2

Voltage across each is 8 V.

I_1=V/R_1=4 extup{ Amp}

I_2=V/R_2=2 extup{ Amp}

3-VR3-1.33 Amp

Total current

I_1+I_2+I_3

or simply

V Reg 8/1.1- 7.33 Amp

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