Question

Show the calculations for both problems.

8) 575.9 g of AI(NO3)(molar mass = 212.996g/mol) was dissolved in 17.89 kg of water. What is the boiling point of this solution? Boiling point of pure water is 100.00 °C and the boiling point constant is 0.510 °C. A) 0.0771 °C (B) 100.077 °C C) 0.308 °C D) 100.308 °C E) 99.692 °C F) 99.923 °C 100=0.510 x. 1511 9) Calculate the solubility of carbon dioxide in water at 10.0 °C and a pressure of 3.00 atm. The solubility of carbon dioxide is 0.0791 mol/L water at 10.0 °C and 1.00 atm. A) 4.21 M B) 0.237 M C 0.0264 M D) 0.0791 M E) 12.6 M

Answer 1

i= 4 for Al(NO3)3, since it prodcue 4 ions in solution 0.510 °C Kg/mol Boiling point elivation ATb = Kbf xm xi Where given boiling point elivation constant Kb = Molality m= 0.1511 mol/ kg ATb = To – Tsol Tb =boiling point of solvet = 100.0 °C Tsol =Boiling point of solution= ? So 4 ATb = Tsol - Tb = Kb x mx i = 0.510 °C Kg mol-1 * 0.15114 mol kg-1 * = 0.3083 °C Tsol-Tb = 0.3083 °C Tsol = Tb + 0.3083 °C 100.0 °C + 0.3083 °C 100.308 °C So boiling point elivation of solution = 100.308 °C