Write a Swift program to
Check whether a year between 2000 and 2500 is a leap year, and
output results.
var index = 2000
/*Iterating from 2000 to 2500*/
while index < 2500 {
/*Checking if year is leap year*/
let isLeapYear = ((index % 4 == 0) && (index % 100 != 0) ||
(index % 400 == 0))
/*If yes than print the year*/
if isLeapYear {
print(index)
}
index = index + 1
}

Note : Please comment below if you have concerns. I am here to help you
If you like my answer please rate and help me it is very Imp for me
Write a Swift program to Check whether a year between 2000 and 2500 is a leap...
Write a program that accepts a year and determines whether the year is a leap year. Use the mod function. The output should be the variable extra_day, which should be 1 if the year is a leap year and 0 otherwise. The rules for determining leap years in the Gregorian calendar are as follows: All years evenly divisible by 400 are leap years. Years evenly divisible by 100 but not by 400 are not leap years. Years divisible by 4...
4) Write a shell script to find whether a year was leap year or not. The script will take input from user. The user will enter a year (will only input a valid year) e.g. 1957. The output will be it's a leap year" if it is and "It's not a leap year" if it is not
solve in python In the planet Utopia a year is a leap year in this century and previous century between years 45 and 450, if it is divisible by 30, Write a program that calculates whether a given year is a leap year in UTOPIA. Input: The year in 4 digits between 45 and 450. You need to check the input year. When the input year is less than 45 or greater than 450 then use a loop to generate...
PLEASE WRITE CODE FOR C++ ! Time Validation, Leap Year and Money Growth PartA: Validate Day and Time Write a program that reads a values for hour and minute from the input test file timeData.txt . The data read for valid hour and valid minute entries. Assume you are working with a 24 hour time format. Your program should use functions called validateHour and validateMinutes. Below is a sample of the format to use for your output file timeValidation.txt : ...
(python) Leap Year Detector Design a program that asks the user to enter a year, and then displays a message indicating whether that year is a leap year or not. Use the following logic to develop your algorithm: If the year is evenly divisible by 100 and is also evenly divisible by 400, then it is a leap year. For example, 2000 is a leap year but 2010 is not. If the year is not evenly divisible by 100, but...
Python Programming Task 2: Leap Years Part A - Is this a leap year? Write a function is leap year(year) that calculates whether a given (CE) year is a leap year. The function must: • take one argument: a positive integer representing a year (assumed to be CE) • return True if that year was a leap year; return False if not NOTE: all years that are divisible by four are leap years, unless they are also divisible by 100,...
the instructions are: A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are:1) The year must be divisible by 42) If the year is a century year...
FINDING THE LEAP YEARS (14 points) From Wikipedia, "A leap year (also known as an intercalary year or bissextile year) is a calendar year containing one additional day (or, in the case of lunisolar calendars, a month) added to keep the calendar year synchronized with the astronomical or seasonal year." In the Gregorian calendar, which is in use today, to determine leap year: A year is a leap year if it is divisible by 400 Or it is divisible by...
#1 Write a MATLAB script to solve: Leap Year Program (practice your IF statements!) Write a code to determine if a year is considered a leap year or not? Display to the screen if the year is a leap year or not. Use num2str() and display() or fprintf(). In the Gregorian calendar three criteria must be taken into account to identify leap years: The year is evenly divisible by 4 (Exceptions 1700, 1800, and 1900); If the year can be...
In Python 3 please 3.28 LAB: Leap year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To account for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4...