Question

I have a 2D character array like this: [ [1 D E F G H]

  [2 C E]

[3 A C]

[4 H I J]

  [5 A B D]]

How do you make a character array consisting of distinct alphabets?

That is the output should be [A B C D E F G H I J].

I need a C++ code for the same.

Answer 1

Here is the solution to above problem. Please refer to code screenshot for indentation help and read code comments for more help.

I am using c++ map to make sure the characters are unique similarly you can use another character array

char C[] to mark all the unique characters just like the map

C++ Code

#include<iostream>
#include<string.h>
#include<map>
using namespace std;

int main()
{
   //using map to store only unique characters
   map<char,bool> M;
   //making the array
   char A[][5]={{'D','E','F','G','H'},{' ',' ','C','E'},{' ',' ','A','C'},{' ','H','I','J'},{' ','A','B','D'}};
   //traversing the array
   for(int i=0;i<5;++i)
   {
       for(int j=0;j<5;++j)
       {
           if(A[i][j]!=' '&& A[i][j]!='\0')
           M[A[i][j]]=true;
       }
   }
   char B[100];
   int j=0;
   //storing unique value in new array
   for(auto i=M.begin();i!=M.end();++i)
   {
       B[j++]= i->first;
   }
   //compting string length
   int length= strlen(B);
   //displaying the new array
   for(int i=0;i<length-1;++i)
       {
           cout<<B[i]<<" ";
       }
  
   return 0;
  
}

OUTPUT OF THE CODE

SCREENSHOT OF THE CODE